State the law of conservation of energy for conservative forces and explain how it is modified for non-conservative forces.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $1$. For conservative forces: The law of conservation of mechanical energy states that if only conservative forces (like gravitational or electrostatic forces) act on a system,the total mechanical energy $(E = K + U)$ remains constant. Mathematically,$\Delta E = \Delta K + \Delta U = 0$,which implies $E_{initial} = E_{final}$.
$2$. For non-conservative forces: When non-conservative forces (like friction or air resistance) act on a system,the total mechanical energy is not conserved. Instead,the work done by non-conservative forces $(W_{nc})$ is equal to the change in total mechanical energy: $W_{nc} = \Delta E = (K_f + U_f) - (K_i + U_i)$. This work is typically dissipated as thermal energy.

Explore More

Similar Questions

The work done by the force $\vec{F} = x^2 \hat{i} + y^2 \hat{j}$ around the closed path $OABC$ shown in the figure is:

$A$ body is moved along a closed loop. Is the work done in moving the body necessarily zero? If not,state the condition under which work done over a closed path is always zero.

If potential energy is given by $U = \frac{a}{r^2} - \frac{b}{r}$,find the maximum force. (Given $a = 2, b = 4$)

In a gravitational field,if the work done along paths $1, 2$ and $3$ is ${W_1}, {W_2}$ and ${W_3}$ respectively,then:

Is the work done by non-conservative forces always negative? Discuss.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo